A country, called Simpleland, has a language with a small vocabulary of just “the”, “on”, “and”, “go”, “round”, “bus”, and “wheels”. For a word count vector with indices ordered as the words appear above, what is the word count vector for a document that simply says “the wheels on the bus go round and round.”

Please enter the vector of counts as follows: If the counts were ["the"=1, “on”=3, "and"=2, "go"=1, "round"=2, "bus"=1, "wheels"=1], enter 1321211.
1 point

Answers

Answer 1

Answer:

umm that is a todler song

Explanation:

umm that is a todler song that they sing to them when there crying

Answer 2

A country, called Simpleland, has a language with a small vocabulary of just “the”, “on”, “and”, “go”, “round”, “bus”, and “wheels”. As per the given scenario, the vector of counts will be 2111211. The correct option is C.

What are the ways to count items in a vector?

C++ has a built-in function that counts the length of the vector. Size is the function's name ().

It returns the size or total number of elements of the vector that was utilized to create it. There is no need for debate.

The number of observations (rows) includes deleted observations as well. In an SAS data collection, there can be a maximum of 2 63-1 observations, or roughly 9.2 quintillion observations. For the majority of users, going above that limit is quite rare.

The vector of counts in the above scenario will be 2111211.

Thus, the correct option is C.

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Related Questions

Write a program that reads in 10 numbers from the user and stores them in a 1D array of size 10. Then, write BubbleSort to sort that array – continuously pushing the largest elements to the right side

Answers

Answer:

The solution is provided in the explanation section.

Detailed explanation is provided using comments within the code

Explanation:

import java.util.*;

public class Main {

//The Bubble sort method

public static void bb_Sort(int[] arr) {  

   int n = 10; //Length of array  

   int temp = 0; // create a temporal variable  

   for(int i=0; i < n; i++){  

         for(int j=1; j < (n-i); j++){  

           if(arr[j-1] > arr[j]){  

               // The bubble sort algorithm swaps elements  

               temp = arr[j-1];  

               arr[j-1] = arr[j];  

               arr[j] = temp;  

             }  

         }            

         }  

        }

 public static void main(String[] args) {

   //declaring the array of integers

   int [] array = new int[10];

   //Prompt user to add elements into the array

   Scanner in = new Scanner(System.in);

   //Use for loop to receive all 10 elements

   for(int i = 0; i<array.length; i++){

     System.out.println("Enter the next array Element");

     array[i] = in.nextInt();

   }

   //Print the array elements before bubble sort

   System.out.println("The Array before bubble sort");

   System.out.println(Arrays.toString(array));

   //Call bubble sort method

   bb_Sort(array);  

               

   System.out.println("Array After Bubble Sort");  

   System.out.println(Arrays.toString(array));

 }

}

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